How do you find the point (x,y) on the unit circle that corresponds to the real number t=(11pi)/6? Trigonometry Right Triangles Relating Trigonometric Functions 1 Answer jess_r Feb 7, 2017 ((sqrt3)/2, -1/2) Explanation: (11pi)/6 corresponds to 330 degrees on the unit circle, which also has the same point values as pi/6, but the y value is negative because it is in the 4th quadrant. Answer link Related questions What does it mean to find the sign of a trigonometric function and how do you find it? What are the reciprocal identities of trigonometric functions? What are the quotient identities for a trigonometric functions? What are the cofunction identities and reflection properties for trigonometric functions? What is the pythagorean identity? If sec theta = 4, how do you use the reciprocal identity to find cos theta? How do you find the domain and range of sine, cosine, and tangent? What quadrant does cot 325^@ lie in and what is the sign? How do you use use quotient identities to explain why the tangent and cotangent function have... How do you show that 1+tan^2 theta = sec ^2 theta? See all questions in Relating Trigonometric Functions Impact of this question 5574 views around the world You can reuse this answer Creative Commons License