Question

How do you find the point (x,y) on the unit circle that corresponds to the real number `t=(11pi)/6`?

Answer 1

(`(sqrt3)/2`, -`1/2`)

Explanation:

`(11pi)/6` corresponds to 330 degrees on the unit circle, which also has the same point values as `pi/6`, but the y value is negative because it is in the 4th quadrant.