Question

How do you find the polar equation for `x-3y=1`?

Answer 1

Please see the explanation.

Explanation:

Substitute `rcos(theta)` for x and `rsin(theta)` for y:

`rcos(theta) - 3rsin(theta) = 1`

Divide both sides by `cos(theta) - 3sin(theta)`

`r = 1/(cos(theta) - 3sin(theta))`