# How do you find the product #(2a+9)(5a-6)#?

##### 1 Answer

#### Explanation:

Notice that these are factors.

You can use the **FOIL** method or the **Distributive Property** .

What is **FOIL** ???

**FOIL- First Outer Inner Last**

#(2a+9)(5a-6)#

**First:** Multiply the first term in the first factor with the first term in the second factor. NB: both numbers are the first of both factors.

#2axx5a=10a^2#

**Outer:** Multipy the first term in the first factor with the last term in the second factor. NB: both numbers are the last of both factors.

#2axx-6=-12a#

**Inner:** Multiply the last term in the first factor with the first term in the second factor. NB: both numbers are innermost numbers.

#9xx5a=45a#

**Last:** Multiply the last term in the first factor with the last term in the second factor. NB: both numbers are the last numbers of each factor.

#9xx-6=-54#

**Now add the numbers.**

#10a^2+(-12a)+45a+(-54)#

#10a^2-12a+45a-54#

#10a^2+33a-54#

What is the **Distributive Property** ???

The distributive property is simply taking the first term in the first factor and multiplying it by the second term.

#2a(5a-6)=10a^2-12a#

Next, take the second term in the first factor and mutilply it by the second factor.

#9(5a-6)=45a-54#

Add the products

#(10a^2-12a)+(45a-54)#

#10a^2-12a+45a-54#

#10a^2+33a-54#

I hope this was well explained.

Follow the same steps and try to solve

You should get

All the best!