How do you find the product #(8h-4n)^2#?

1 Answer
Feb 19, 2017

Answer:

See the entire solution process below:

Explanation:

We can rewrite this expression as:

#(8h - 4n)(8h - 4n)#

To multiply these two terms you multiply each individual term in the left parenthesis by each individual term in the right parenthesis.

#(color(red)(8h) - color(red)(4n))(color(blue)(8h) - color(blue)(4n))# becomes:

#(color(red)(8h) xx color(blue)(8h)) - (color(red)(8h) xx color(blue)(4n)) - (color(red)(4n) xx color(blue)(8h)) + (color(red)(4n) xx color(blue)(4n))#

#64h^2 - 32hn - 32hn + 16n^2#

We can now combine like terms:

#64h^2 + (-32 - 32)hn + 16n^2#

#64h^2 - 64hn + 16n^2#