How do you find the product of #(3d+3)(2d^2+5d-2)#?

1 Answer
Mar 25, 2017

Answer:

See the entire solution process below:

Explanation:

To multiply these two terms you multiply each individual term in the left parenthesis by each individual term in the right parenthesis.

#(color(red)(3d) + color(red)(3))(color(blue)(2d^2) + color(blue)(5d) - color(blue)(2))# becomes:

#(color(red)(3d) xx color(blue)(2d^2)) + (color(red)(3d) xx color(blue)(5d)) - (color(red)(3d) xx color(blue)(2)) + (color(red)(3) xx color(blue)(2d^2)) + (color(red)(3) xx color(blue)(5d)) - (color(red)(3) xx color(blue)(2))#

#6d^3 + 15d^2 - 6d + 6d^2 + 15d - 6#

We can now group and combine like terms:

#6d^3 + 15d^2 + 6d^2 - 6d + 15d - 6#

#6d^3 + (15 + 6)d^2 + (-6 + 15)d - 6#

#6d^3 + 21d^2 + 9d - 6#