How do you find the product of #(3r+2)(9r^2+6r+4)#?

1 Answer
Aug 16, 2017

Answer:

#27r^3+36r^2+24r+8#

Explanation:

#"each term in the second factor must be multiplied by "#
#"each term in the first factor"#

#(color(red)(3r+2))(9r^2+6r+4)#

#=color(red)(3r)(9r^2+6r+4)color(red)(+2)(9r^2+6r+4)#

#=(color(red)(3r)xx9r^2)+(color(red)(3r)xx6r)+(color(red)(3r)xx4)#
#color(white)(xx)+(color(red)(2)xx9r^2)+(color(red)(2)xx6r)+(color(red)(2)xx4)#

#=27r^3+18r^2+12r+18r^2+12r+8#

#=27x^3+36r^2+24r+8#