# How do you find the product of (4b+6)(b-4)?

Dec 24, 2016

$4 {b}^{2} - 10 b - 24$

#### Explanation:

To find the product of these two terms you need to first cross multiply each term in the parenthesis on the left by each term in the parenthesis on the right:

$\left(\textcolor{red}{4 b + 6}\right) \left(\textcolor{b l u e}{b - 4}\right) \to$

$\left(\textcolor{red}{4 b} \cdot \textcolor{b l u e}{b}\right) - \left(\textcolor{red}{4 b} \cdot \textcolor{b l u e}{4}\right) + \left(\textcolor{red}{6} \cdot \textcolor{b l u e}{b}\right) - \left(\textcolor{red}{6} \cdot \textcolor{b l u e}{4}\right) \to$

$4 {b}^{2} - 16 b + 6 b - 24$

Next we can combine like terms:

$4 {b}^{2} + \left(- 16 + 6\right) b - 24$

$4 {b}^{2} + \left(- 10\right) b - 24$

$4 {b}^{2} - 10 b - 24$