# How do you find the product of (4c+1)(2c+1)?

Sep 7, 2016

$8 {c}^{2} + 6 c + 1$

#### Explanation:

We have: $\left(4 c + 1\right) \left(2 c + 1\right)$

Let's expand the parentheses:

$= \left(4 c\right) \left(2 c\right) + \left(4 c\right) \left(1\right) + \left(1\right) \left(2 c\right) + \left(1\right) \left(1\right)$

$= 8 {c}^{2} + 4 c + 2 c + 1$

$= 8 {c}^{2} + 6 c + 1$