How do you find the product of #(8 - 9x)^2#?

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Answer 1 · 2017-02-09T13:48:58

See the entire solution process below:

We can rewrite this expression as:

#(color(red)(8) - color(red)(9x))(color(blue)(8) - color(blue)(9x))# which becomes:

#(color(red)(8) xx color(blue)(8)) - (color(red)(8) xx color(blue)(9x)) - (color(red)(9x) xx color(blue)(8)) + (color(red)(9x) xx color(blue)(9x))#

#64 - 72x - 72x + 81x^2#

We can now combine like terms:

#64 - (72 + 72)x + 81x^2#

#64 - 144x + 81x^2#

#81x^2 - 144x + 64#