How do you find the product of #(n+3)^2#?

1 Answer
Mar 13, 2018

Answer:

#n^2+6n+9#

Explanation:

We have #(n+3)^2#. We can write this out as:

#(n+3)(n+3)#

Use FOIL. In FOIL, we first multiply the first variable, #n#, with both of the numbers in the second bracket. Then, we multiply the constant in the first bracket will all of the numbers in the second bracket. Then we add our subtract as needed.

We have:

#n(n)+n(3)+3(n)+3(3)#

#n^2+3n+3n+9#

#n^2+6n+9#

Our answer. Another method is to remember that #(a+b)^2=a^2+2ab+b^2#. We could have inputted directly.