How do you find the product of #(n-5)(n+1)#?

2 Answers
May 2, 2018

Answer:

#n^2 -4n -5#

Explanation:

=#(n-5)(n+1)#
=#[n(n+1) -5(n+1)]#
=#n^2 +n -5n -5#
=#n^2 -4n -5#

HAPPY LEARNING!!

May 2, 2018

Answer:

#n^2-4n-5#

Explanation:

Use the FOIL method: First Outer Inner Last

  • First: #n*n=n^2#
  • Outer: #n*1=n#
  • Inner: #-5*n=-5n#
  • Last: #-5*1=-5#

So you have

#n^2+n-5n-5#

Simplify

#n^2-4n-5#