How do you find the product of #(t+3)(t^2+4t+7)#?

1 Answer
Jan 1, 2018

Answer:

#t^3+7t^2+19t+21#

Explanation:

#"each term in the second factor is multiplied by each"#
#"term in the first factor"#

#rArr(color(red)(t+3))(t^2+4t+7)#

#=color(red)(t)(t^2+4t+7)color(red)(+3)(t^2+4t+7)#

#"distribute the brackets and collect like terms"#

#=t^3+4t^2+7t+3t^2+12t+21#

#=t^3+7t^2+19t+21#