# How do you find the product of (w+4)(w^2+3w-6)?

Mar 27, 2017

$\left(w + 4\right) \left({w}^{2} + 3 w - 6\right) = {w}^{3} + 7 {w}^{2} + 6 w - 24$

#### Explanation:

We use distributive property i.e. multiplying $\left({w}^{2} + 3 w - 6\right)$ first by $w$ and then by $4$ and then adding the two.

$\left(w + 4\right) \left({w}^{2} + 3 w - 6\right)$

= $w \left({w}^{2} + 3 w - 6\right) + 4 \left({w}^{2} + 3 w - 6\right)$

= $w \times {w}^{2} + w \times 3 w - w \times 6 + 4 \times {w}^{2} + 4 \times 3 w - 4 \times 6$

= ${w}^{3} + 3 {w}^{2} - 6 w + 4 {w}^{2} + 12 w - 24$

= ${w}^{3} + 7 {w}^{2} + 6 w - 24$