# How do you find the product of (x^2-3)(2x^2+4x-5)?

Apr 27, 2017

$2 {x}^{4} + 4 {x}^{3} - 11 {x}^{2} - 12 x + 15$

#### Explanation:

Multiply each term of $2 {x}^{2} + 4 x - 5$ by ${x}^{2}$
$\left(2 {x}^{4} + 4 {x}^{3} - 5 {x}^{2}\right) - 3 \left(2 {x}^{2} + 4 x - 5\right)$

Multiply each term of $2 {x}^{2} + 4 x - 5$ by $- 3$
$2 {x}^{4} + 4 {x}^{3} - 5 {x}^{2} - 6 {x}^{2} - 12 x + 15$

Simplify to get
$2 {x}^{4} + 4 {x}^{3} - 11 {x}^{2} - 12 x + 15$#