How do you find the product of #(x3)^2#?
2 Answers
From here we can just FOIL; first, outer, inner, last. Multiply the first term in the first bracket (x), by the FIRST term in the second bracket (x), giving us
Collect like terms:
And you're done!
Explanation:

Let's say
#A=x3# (this is to help you understand).
So then we would have#A^2# , which gets you#AxxA# . 
Now let's apply that back into the original problem.
#(x3)^2=(x3)xx(x3)=(x3)(x3)# 
We can use the Distributive Property to make this more easily readable:
#\color(red)(x(x3))+\color(green)((3)(x3))#
Simplify by reapplying Distributive Property:
#\color(red)(x(x)+x(3))+\color(green)((3)(x)+(3)(3))# 
And multiply...
#x^2+(3x)+(3x)+9=x^36x+9#