How do you find the product #[(t^2+3t-8)-(t^2-2t+6)](t-4)#? Algebra Polynomials and Factoring Multiplication of Polynomials by Binomials 1 Answer Anjali G · Sonnhard Jun 6, 2018 #[(t^2+3t-8)-(t^2-2t+6)] (t-4) = 5t^2-34t+56# Explanation: # [(cancel(t^2)+3t-8)-(cancel(t^2)-2t+6)] (t-4)# # = (5t-14)(t-4)# We have the first term: #t^2+3t-8-t^2+2t+6=5t-14# so we get # [(cancel(t^2)+3t-8)-(cancel(t^2)-2t+6)] (t-4)# # = (5t-14)(t-4)# #(5t-14)(t-4)=5t^2-14t-20t+56# Combining like terms, we get: #5t^2-34t+56# Answer link Related questions What is FOIL? How do you use the distributive property when you multiply polynomials? How do you multiply #(x-2)(x+3)#? How do you simplify #(-4xy)(2x^4 yz^3 -y^4 z^9)#? How do you multiply #(3m+1)(m-4)(m+5)#? How do you find the volume of a prism if the width is x, height is #2x-1# and the length if #3x+4#? How do you multiply #(a^2+2)(3a^2-4)#? How do you simplify #(x – 8)(x + 5)#? How do you simplify #(p-1)^2#? How do you simplify #(3x+2y)^2#? See all questions in Multiplication of Polynomials by Binomials Impact of this question 3184 views around the world You can reuse this answer Creative Commons License