# How do you find the product t(4t^2+15t+4)-4(3t-1)?

Apr 11, 2018

$4 {T}^{3} + 15 {T}^{2} - 8 T - 4$

#### Explanation:

$\left(4 {T}^{3} + 15 {T}^{2} + 4 T\right) - \left(12 T + 4\right)$
$4 {T}^{3} + 15 {T}^{2} + 4 T - 12 T - 4$
$4 {T}^{3} + 15 {T}^{2} - 8 T - 4$