How do you find the quotient of #(2y^4-3y^2+1)div(y-1)# using long division?

1 Answer
Gaya3
Oct 4, 2017

#2y^3+2y^2-y-1#

Explanation:

#" "" "2y^3+2y^2-y-1#
#y-1|bar(cancel(2y^4)+0y^3-3y^2+0y+1)|#
#" "" " cancel(2y^4)-2y^3 #
#" "" "bar(0+cancel(2y^3)-3y^2+0y+1)#
#" "" " 0+cancel(2y^3)-2y^2#
#" "" "bar( 0+00 cancel(-1y^2)+0y+1)#
#" "" " 0+00cancel(-1y^2)+y#
#" "" "bar( 0+00+00cancel(-1y+1)#
#" "" " 0+00+00cancel(-1y+1#
#" "" "bar(................................)#

Note:
The sign is changed (+ to - or - to +) when the term is multiplied with the term in the quotient.

Related questions
See all questions in Long Division of Polynomials
Impact of this question
2204 views around the world
You can reuse this answer
Creative Commons License