# How do you find the range of # f(x)=1/(x-3)#?

##### 1 Answer

Jun 18, 2018

#### Explanation:

#"let "y=1/(x-3)#

#"rearrange making "x" the subject"#

#y(x-3)=1#

#xy-3y=1#

#x=(1+3y)/y#

#"the denominator "!=0#

#"range "y in(-oo,0)uu(0,oo)#

graph{1/(x-3) [-10, 10, -5, 5]}