# How do you find the range of f(x)=[3x-4] if the domain is (0, 1, 2, 3)?

Nov 14, 2017

See a solution process below:

#### Explanation:

To find the range, substitute each value of the domain into the formula and calculate the result:

For x = 0

$f \left(0\right) = \left[\left(3 \times 0\right) - 4\right]$

$f \left(0\right) = \left[0 - 4\right]$

$f \left(0\right) = - 4$

For x = 1

$f \left(1\right) = \left[\left(3 \times 1\right) - 4\right]$

$f \left(1\right) = \left[1 - 4\right]$

$f \left(1\right) = - 3$

For x = 2

$f \left(2\right) = \left[\left(3 \times 2\right) - 4\right]$

$f \left(2\right) = \left[6 - 4\right]$

$f \left(2\right) = 2$

For x = 3

$f \left(3\right) = \left[\left(3 \times 3\right) - 4\right]$

$f \left(3\right) = \left[9 - 4\right]$

$f \left(3\right) = 5$

Therefore, the Range is: $\left\{- 4 , - 3 , 2 , 5\right\}$