How do you find the range of f(x)=x^2+4x+12 with the domain of 0<=x<=5?
1 Answer
Sep 24, 2015
The answer is 12
Explanation:
On simplifying ,
f(x) =
As 0
2
Therefore, 4
4+8
12
The answer is 12
On simplifying ,
f(x) =
As 0
2
Therefore, 4
4+8
12