How do you find the range of #f(x)=x^2-x-2#?
1 Answer
Jun 28, 2015
Range 0f f(x) = x^2 - x - 2
Explanation:
x of vertex -> x = -b/2a = 1/2
y of vertex -> f(1/2) = 1/4 - 1/2 - 2 = -9/4
The graph of f(x) is a parabola that opens upward (a > 0) and with Minimum (1/2, -9/4).
Range of f(x) -> (+infinity, -9/4) and (-9/4, +infinity)
