# How do you find the range of f(x)=x^2-x-2?

The range is $\left[- \frac{9}{4} , + \infty\right)$
The domain is $R$ and we have that
y=(x^2-x+1/4)-2-1/4=>y=(x-1/2)^2-9/4=>y+9/4=(x-1/2)^2=> y+9/4>=0=>y>=-9/4