# How do you find the range of #h(x) = x/2# if {-2, -2, 0, 1/2}?

##### 1 Answer

Nov 25, 2017

See a solution process below:

#### Explanation:

Substitute each value in the **Domain** for **Range** of the function:

**For #x = -2#:**

**For #x = -2 ("Again?")#:**

**For #x = 0#:**

**For #x = 1/2#:**

**The Range of the function is:**