How do you find the range of #h(x) = x/2# if {-2, -2, 0, 1/2}?

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Answer 1 · 2017-11-25T23:09:58

See a solution process below:

Substitute each value in the Domain for #color(red)(x)# and calculate #h(x)# to find the Range of the function:

For #x = -2#:

#h(color(red)(x)) = color(red)(x)/2# becomes:

#h(color(red)(-2)) = color(red)(-2)/2#

#h(color(red)(-2)) = -1#

For #x = -2 ("Again?")#:

#h(color(red)(x)) = color(red)(x)/2# becomes:

#h(color(red)(-2)) = color(red)(-2)/2#

#h(color(red)(-2)) = -1#

For #x = 0#:

#h(color(red)(x)) = color(red)(x)/2# becomes:

#h(color(red)(0)) = color(red)(0)/2#

#h(color(red)(-2)) = 0#

For #x = 1/2#:

#h(color(red)(x)) = color(red)(x)/2# becomes:

#h(color(red)(0)) = color(red)(1/2)/2#

#h(color(red)(-2)) = 1/4#

The Range of the function is: #{-1, 0, 1/4}#