# How do you find the range of x^2/(x-5)?

Sep 20, 2015

The range for x is all real number except 5

#### Explanation:

In a quotient function, the denominator can be an number except 0.

You can get the explanation about why the denominator can't be zero in all around the internet or simply ask your teacher

In the question above, the denominator is $x - 5$

So, the denominator will be 0 only if $x - 5 = 0$

Thus it's conclude that only if $x = 5$ the term of $x - 5$ will be equivalent to $0$

The range for $x$ in term ${x}^{2} / \left(x - 5\right)$ then could be any number from $x = - \infty$ to $x = \infty$ except for the number of $x = 5$ which will be left undefined.

Usually the term is written as ${x}^{2} / \left(x - 5\right)$ ,$x \ne 5$ to indicate the range of $x$.