How do you find the range of #y = 3x + 10#?

1 Answer
Sep 20, 2015

Answer:

The range of this function is the whole of #RR# since for any value of #y# there is a value of #x# such that #y = 3x+10#

Explanation:

We can solve for #x# in terms of #y# as follows:

Subtract #10# from both sides to get:

#y - 10 = 3x#

Divide both sides by #3# to get:

#x = (y - 10)/3#

The right hand side is defined for any #y in RR#, so we can always find an #x# that yields a given value of #y#.