How do you find the remainder for #(x^3+6x^2-4x+2)div(x+1)#?

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Answer 1 · 2016-11-02T15:37:32

Use the Remainder Theorem . The remainder is 11

The Remainder Theorm states that:

Given a polynomial, #p(x)#, the remainder, #r(a)#, of the division, #p(x) -: (x - a)#, is equal to the polynomial evaluated at a:

#r(a) = p(a)#

#(x + 1) = (x - -1)#, therefore, #a = -1#

Evaluate the polynomial at -1:

#(-1)^3 + 6(-1)^2 - 4(-1) + 2 = 11#

The remainder is 11.