# How do you find the roots for g(x) = x^2-x-12?

May 23, 2017

$x = 4$ and $x = - 3$

#### Explanation:

We need to factor g(x):

${x}^{2} - x - 12$

$\left(x - 4\right) \left(x + 3\right)$

Now, we simply set each factor equal to zero and solve for x:

$x - 4 = 0$
$x = 4$

$x + 3 = 0$
$x = - 3$