# How do you find the roots of 2m^2-7m-13=-10 using the quadratic formula?

Aug 8, 2017

$\frac{7 \pm \sqrt{73}}{-} 4$

#### Explanation:

First, we must make the equation into the form of

$a {x}^{2} + b x + c$

in order to use the quadratic formula. Adding 10 to both sides of the equation gives us

$2 {m}^{2} - 7 m - 3$

This equation is in the form mentioned above and thus we can now use the quadratic equation to the roots

$a = 2 , b = - 7 , c = - 3$

We substitute these value into the equation to give us

$\frac{- \left(- 7\right) \pm \sqrt{{\left(- 7\right)}^{2} - 4 \left(2\right) \left(- 3\right)}}{- 2 \cdot \left(2\right)}$

Thus, the roots to the equation $2 {m}^{2} - 7 m - 13 = - 10$ would be

$\frac{7 \pm \sqrt{73}}{-} 4$