How do you find the roots, real and imaginary, of y=-(2x-1)^2 + 3x^2 - 2 using the quadratic formula?

1 Answer
Jun 15, 2018

Multiply out the bracket and collect terms in order to put it into standard quadratic form

Explanation:

Multiply out the bracket:
y=-(4x^2-4x+1)+3x^2-2
y=-4x^2+4x-1+3x^2-2
y=-x^2+4x-3

Apply the quadratic formula (-b+-sqrt(b^2-4ac))/(2a):
(-4+-sqrt(16-4*3))/(-2)=(-4+-2)/(-2)=2+-1=1,3