Question

How do you find the roots, real and imaginary, of `y=-(2x-1)^2 -4x^2 - 13x + 4` using the quadratic formula?

Answer 1

`x=(9+-sqrt177)/-16`

Explanation:

Simplify the pattern step by step
`y=-(2x-1)^2-4x^2-13x+4`
`y=-(4x^2-4x+1)-4x^2-13x+4`
`y=-8x^2-9x+3`
By using quadratic formula
`x=(9+-sqrt(81+4*8*3))/-16`
`x=(9+-sqrt177)/-16`