How do you find the roots, real and imaginary, of y=-2x^2 + 7x +6  using the quadratic formula?

Dec 1, 2015

Plug in a, b, c in the quadratic equation which is $\frac{\left(- b\right) \pm \sqrt{{b}^{2} - 4 a c}}{2 a}$

$a =$coefficient of ${x}^{2}$.
$a = - 2$

$b =$ coefficient of $x$.
$b = 7$

$c =$ the constant in the equation.
$c = 6$

$\frac{\left(- 7\right) \pm \sqrt{{\left(7\right)}^{2} - 4 \left(- 2\right) \left(6\right)}}{2 \left(- 2\right)}$