# How do you find the roots, real and imaginary, of y= -4x^2 + x^2 +6 using the quadratic formula?

Jun 9, 2018

color(indigo)("Roots are " x = -sqrt(3/2) , sqrt(3/2)

#### Explanation:

$y = - 4 {x}^{2} + {x}^{2} + 6$

$y = - 3 {x}^{2} + 6$

$a = - 3 , b = 0 , c = 6$

$x = \frac{0 \pm \sqrt{0 + 96}}{-} 8$

$x = \frac{\sqrt{96}}{-} 8 , \frac{\sqrt{96}}{8}$

color(indigo)("Roots are " x = -sqrt(3/2) , sqrt(3/2)