Question

How do you find the roots, real and imaginary, of `y=x^2 + -3x + 14` using the quadratic formula?

Answer 1

`x_1=3/2+sqrt(47)/2i` or `x_2=3/2-sqrt(47)/2i`

Explanation:

Using the formula
`x_{1,2}=-b/(2a)\pm1/(2a)sqrt(b^2-4ac}`
we get
`x_{1,2}=3/2pmsqrt(9/4-56/4)`
this gives
`x_{1,2}=3/2\pm\sqrt(47)/(2)i`