# How do you find the six trigonometric functions of 420 degrees?

May 3, 2015

$\sin 420 = \sin \left(60 + 360\right) = \sin 60 = \frac{\sqrt{3}}{2}$(1)

$\cos 420 = \cos \left(60 + 360\right) = \cos 60 = \frac{1}{2}$ (2)

$\tan 420 = \frac{\left(1\right)}{\left(2\right)} = \sqrt{3}$

$\cot 420 = \frac{1}{\sqrt{3}} = \frac{\sqrt{3}}{3}$

$\sec 420 = \frac{1}{\cos} 420 = 2$

$\sin 420 = \frac{1}{\sin} 420 = \frac{2 \sqrt{3}}{3}$