How do you find the slope and intercept of #12x+4y-2=0#?

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Answer 1 · 2018-04-19T03:13:43

Slope#=m=-3#

#y-#intercept#=b=1/2#

Solve the equation for #y:#

#12x+4y-2=0#

Add #2# to both sides:

#12x+4y=2#

Subtract #12x# from both sides:

#4y=2-12x#

Divide #4# from both sides:

#y=(2-12x)/4#

Simplify:

#y=1/2-3x#

#y=-3x+1/2#

This last equation is now in #y=mx+b# form where

#m# is the slope (the coefficient of the variable #x#)

#b# is the #y-#intercept or the constant

From the equation:

#y=-3x+1/2#

Slope#=m=-3#

#y-#intercept#=b=1/2#