How do you find the slope and intercept of #12x+4y-2=0#?

1 Answer
Apr 19, 2018

Answer:

Slope#=m=-3#

#y-#intercept#=b=1/2#

Explanation:

Solve the equation for #y:#

#12x+4y-2=0#

Add #2# to both sides:

#12x+4y=2#

Subtract #12x# from both sides:

#4y=2-12x#

Divide #4# from both sides:

#y=(2-12x)/4#

Simplify:

#y=1/2-3x#

#y=-3x+1/2#

This last equation is now in #y=mx+b# form where

#m# is the slope (the coefficient of the variable #x#)

#b# is the #y-#intercept or the constant

From the equation:

#y=-3x+1/2#

Slope#=m=-3#

#y-#intercept#=b=1/2#