# How do you find the slope and intercept of 12x+4y-2=0?

Apr 19, 2018

Slope$= m = - 3$

$y -$intercept$= b = \frac{1}{2}$

#### Explanation:

Solve the equation for $y :$

$12 x + 4 y - 2 = 0$

Add $2$ to both sides:

$12 x + 4 y = 2$

Subtract $12 x$ from both sides:

$4 y = 2 - 12 x$

Divide $4$ from both sides:

$y = \frac{2 - 12 x}{4}$

Simplify:

$y = \frac{1}{2} - 3 x$

$y = - 3 x + \frac{1}{2}$

This last equation is now in $y = m x + b$ form where

$m$ is the slope (the coefficient of the variable $x$)

$b$ is the $y -$intercept or the constant

From the equation:

$y = - 3 x + \frac{1}{2}$

Slope$= m = - 3$

$y -$intercept$= b = \frac{1}{2}$