How do you find the slope and intercept of -3x-8y+6=0?

Dec 15, 2015

Slope-Intercept Form:
$y = m x + b$
Where $m$ is the slope and $b$ is the y-intercept.

Original Equation:
$- 3 x - 8 y + 6 = 0$

To put an equation into slope-intercept form, you have to isolate $y$. This means you have to get $y$ by itself:

$- 3 x - 8 y + 6 = 0$

$- 3 x - 8 y = - 6$

$- 8 y = 3 x - 6$

$y = \frac{3 x - 6}{- 8}$

$y = \left(- \frac{3}{8}\right) x + \left(\frac{3}{4}\right)$

Once you have $y$ by itself, all you have to do is determine which number is your slope and which is your intercept.

You should end up with:
$m$ (slope)$= \left(- \frac{3}{8}\right)$
and
$b$ (y-intercept)$= \left(\frac{3}{4}\right)$