How do you find the slope and intercept of #4x-2y=12#?

1 Answer
Jan 20, 2016

Answer:

#m=2#
#a=-6#
#b=3#

Explanation:

Given equation is #4x-2y=12#
Now, general slope equation is #y-y_o=m(x-x_o)# where #m# is the slope of the equation.
IF we rearrange the given equation, we see that it becomes
#2y=4x-12#
Considering #y_o=0#, and taking #4# common in the left hand side and dividing the whole equation by 2, we get what we want. That is
#2y=4(x-3)# Divide by #2# and
#y=2(x-3)#.
Comparing the one we solved with the general equation, we see that #m=2#.

Now, for intercept form equation, the general equation is
#y/a=x/b=1# where #a# is the y-intercept and #b# is the x-intercept.
So rearranging the original equation we had #4x-2y=12# and dividing the equation by #12#, we get
#x/3-y/6=1#
So #a=-6# (since the #y# parameter has a negative value)
and #b-3#