How do you find the slope and intercept of 4x – 2y = 6?

Dec 7, 2015

Using slope-intercept form, the slope of the line $4 x - 2 y = 6$ is $\frac{2}{1}$, and the y-intercept is $\left(0 , - 3\right)$.

Explanation:

The first thing we can notice is that this equation's terms are all easily divisible by $2$, so we can divide all the terms by $2$:

$2 x - y = 3$.

Next, we can manipulate this equation into slope-intercept form, which is $y = m x + b$, where $m =$the slope of the line and $b =$the y-coordinate of the y-intercept. We're trying to isolate $y$, so subtract $2 x$ from both sides:

$- y = - 2 x + 3$.

Now divide both sides/all terms by $- 1$:

$y = 2 x - 3$.

From here, we can clearly see that $m = 2$, or $\frac{2}{1}$, and $b = - 3$, which means the slope is $\frac{2}{1}$ and the y-intercept is $\left(0 , - 3\right)$.

Dec 7, 2015

The slope, $m$, is 2 and the y-intercept, $b$ is $- 3$.

Explanation:

$4 x - 2 y = 6$

Solve for $y$.

Subtract $4 x$ from both sides of the equation.

$- 2 y = - 4 x + 6$

Divide both sides by $- 2$.

$y = \frac{- 4}{- 2} x + \frac{6}{- 2}$

Simplify.

$y = 2 x - 3$

Slope-intercept form is $y = m x + b$, where $m$ is the slope, $2$, and $b$ is the y-intercept, $- 3$.