How do you find the slope and intercept of #-5x - 2y = 18#?

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Answer 1 · 2016-05-06T18:56:19

Slope = #-5/22#

#y#-intercept is #-9# and the point is #(0,-9)#

#x#-intercept is #-3.6# and the point is #(-3.6,0)#

First, we find the slope and #y#-intercept

Now, the equation of a line is of the form #color(red)(y=mx+c)#

Where, #m# is the slope of the line and #c# is the #y#-intercept.

Let us write the given line in the standard form:

#y=-(5x)/2-18/2#

#=>y=-(5x)/2-9#

Comparing #y=mx+c# to the given equation, #y=-(5x)/2-9#

#m=-5/2# and #c=-9#

#=># Slope #= -5/2# and #y#-intercept #= -9#

Next, we work out the #x#-intercept.

The #x#-intercept is the point where the line cuts the #x#-axis. i.e. to find the point when #y=0#.

Pretty simple.

Here is a step-by-step calculate the #x#-intercept .

enter image source here

#x#-intercept is #-3.6#.