How do you find the slope and intercept of #6x = 7y + 7#?

1 Answer
Aug 9, 2016

Answer:

slope is #=6/7#
#x#-intercept is #x=7/6#
#y#-intercept is #y=-1#

Explanation:

#y=mx +c# where #m# is the slope
In the equation #6x=7y+7#
or
#7y=6x-7#
or
#y=(6x)/7-7/7#
or
#y=(6x)/7-1#
slope is #=6/7#
#x#-intercept is when #y=0#
So
#0=(6x)/7-1#
or
#(6x)/7=1#
or
#x=7/6#
Similarly
#y#-intercept is when #x=0#
or
#y=6/7(0)-1#
or
#y=-1#