How do you find the slope and intercept of #7x=5y#?

2 Answers
May 25, 2018

Answer:

The slope is #7/5# and the y-intercept is #0#.

Explanation:

Reverse the equation.

#5y=7x#

Divide both sides by #5#.

#y=7/5x#

This equation is in slope-intercept form:

#y=mx+b#,

where #m# is the slope, and #b# is the y-intercept.

In the equation #y=7/5x#, the slope is #7/5# and the y-intercept is #0#.

graph{y=7/5x [-10, 10, -5, 5]}

May 25, 2018

Answer:

Slope: #7/5#, Intercepts #(0,0)#

Explanation:

#7x = 5y -> y=7/5x#

Recall the equation of a straight line in slope #(m)# and #y-#intercept #(c)# form is: #y=mx+c#

In this example: #m=7/5 and c=0#

Also, #x=0# where #y=0#

Hence, #y# is a straight line through the origin with slope #7/5# as shown below.

graph{7/5x [-11.46, 11.04, -4.785, 6.465]}

So, slope of #y# is #7/5# and both #x and y# Intercepts occur at the point #(0,0)#