# How do you find the slope and intercept to graph 2x-y= 1?

Aug 13, 2018

$\text{see explanation}$

#### Explanation:

$\text{the equation of a line in "color(blue)"slope-intercept form}$ is.

•color(white)(x)y=mx+c

$\text{where m is the slope and c the y-intercept}$

$\text{rearrange "2x-y=1" into this form}$

$y = 2 x - 1$

$\text{with slope "=2" and y-intercept } = - 1$

$\text{Plot the point } \left(0 , - 1\right)$

$\text{from this point move 2 units vertically and 1 unit to}$
$\text{the right}$

$\left(0 , - 1\right) \to \left(1 , 1\right)$

$\text{repeat this from the point } \left(1 , 1\right)$

$\left(0 , - 1\right) \to \left(1 , 1\right) \to \left(2 , 3\right)$

$\text{Plot these points and draw a straight line through them}$
graph{(y-2x+1)((x-0)^2+(y+1)^2-0.04)((x-1)^2+(y-1)^2-0.04)((x-2)^2+(y-3)^2-0.04)=0 [-10, 10, -5, 5]}