Question

How do you find the slope and intercepts of `x-2y=8`?

Answer 1

`"slope " =1/2," intercepts are " -4 , 8`

Explanation:

The equation of a line in `color(blue)"slope-intercept form"` is.

`color(red)(bar(ul(|color(white)(2/2)color(black)(y=mx+b)color(white)(2/2)|)))`
where m represents the slope and b, the y-intercept.

`"Rearrange " x-2y=8" into this form"`

Leave - 2y on the left side and subtract x from both sides.

`cancel(x)cancel(-x)-2y=-x+8`

`rArr-2y=-x+8`

divide ALL terms on both sides by - 2

`(cancel(-2) y)/cancel(-2)=(-1)/(-2)x+8/(-2)`

`rArry=1/2x-4larr" now in above form"`

`rArr"slope " =1/2" and y-intercept " =-4`

To find the x-intercept, substitute y = 0 into the equation and solve for x.

`rArrx-(2xx0)=8rArrx=8" is the x-intercept"`