# How do you find the slope and the intercepts of 3x-4y=12?

I would try rearranging your equation by isolating $y$ on the left as:
$y = \frac{3}{4} x - \frac{12}{4}$
$y = \frac{3}{4} x - 3$
slope=$\frac{3}{4}$
y-intercept=$- 3$ (for $x = 0$)
x-intercept=$4$ (for $y = 0$)