# How do you find the slope and y intercept for y=(2/3)x-7?

The equation of a straight line in slope-intercept form is $y = m x + b$, where $m$ is the slope, and $b$ is the y-intercept.
Your equation is already in point-intercept form: $y = \frac{2}{3} x - 7$.
The slope, $m$, is $\frac{2}{3}$, and the y-intercept, $b$, is $- 7$.