How do you find the slope and y intercept for #y + 4 = 2x#?

2 Answers
Mar 11, 2016

Answer:

#m=2#

#q=-4#

Explanation:

We need to transform the equation in the form:

#y=mx+q#

where

slope=#m#

and

#y_(nn)=q# (with #y_(nn)# as #y# intercept)

#y+4=2x<=>y=2x-4#

Therefore:

#m=2#

#q=-4#

graph{2x-4 [-3.862, 6.004, -4.428, 0.506]}

Mar 11, 2016

Answer:

Same thing just, presented a bit differently!

#color(blue)("The slope " = " " 2)#
#color(blue)(" " y_("intercept ")=-4)#

Explanation:

Given:#" "y+4=2x#

You could transform this into the standard format of #y = mx+c # but in this case we do not have to do so to determine what we are asked to.

'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

The y-intercept is when #x=0# This is because the y-axis crosses the x-axis at #x=0#

So we write the equation as: #y+4=2xx0#

But #2xx0 = 0# giving

#color(brown)(y+4=0)#

Subtract#" "color(blue)( 4 )" "#from both sides

#color(brown)(y+4color(blue)(-4)=color(blue)(-4))#

But #4-4 = 0 # giving

#color(green)(y+0=-4" so " y_("intercept")=-4)#
'~~~~~~~~~~~~~~~~~~~~~~~~~~~

The slope (gradient) is the number in front of #x" ( the coefficient of "x) # which is 2

#color(green)("The slope "=2)#
'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~