# How do you find the slope and y intercept of x + 3y = 12?

Subtract $x$ from both sides to get:
$3 y = - x + 12$
Divide both sides by $3$ to get:
$y = \left(- \frac{1}{3}\right) x + 4$
This is of the standard slope intercept form $y = m x + c$ with slope $m = - \frac{1}{3}$ and intercept $c = 4$.