# How do you find the slope given 6x+3y=12?

$- 2$
For a linear equation in standard form $y = m x + c$, the slope is $m$ and the y-intercept is $c$.
In this case, the standard form of $6 x + 3 y = 12$ is $y = - 2 x + 4$ and hence the slope is $- 2$.