How do you find the slope given #y=3#?

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Answer 1 · 2018-03-26T08:32:39

Slope is #0#,

Slope of a line in the form of #y=mx+b# is #m#, and is found by,

#m=(y_2-y_1)/(x_2-x_1)#

We have the equation #y=3#, which means that the #y# value is constant, and so,

#m=(3-3)/(x_2-x_1)#

#=0/(x_2-x_1)#

#=0#

So, the slope is #0#.

graph{y=0x+3 [-10, 10, -5, 5]}

As you can see here, there is no change in #y# from #x#, and so no slope exists.